Question

if you simplify [(x-2)/(x+2)]+[(x-1)/(x+2)] all over [(x)/(x+1)]-[(2x-3)/(x)] is the answer: -3/-x+3?

Answer 1

UGHHH instead of [(x-1)/(x+2)] it is actually: [(x-1)/(x+1)]

Answer 2

hmm i get something different
-2x(x^2-2)/(x+2)(x^2-x-3)

Answer 3

okay..that is why i'm asking. I got really confused. I hope the way I tried to explain what the equation looks like was not too challenging.

Answer 4

Could you somehow show me how you got this answer?

Answer 5

for the top part you need to combine fractions
common denominator is (x+2)(x+1)
you should get:
[(x-2)(x+1)+(x+2)(x-1)]/(x+2)(x+1)

In the bottom part do the same thing
common denominator is x(x+1)
you should get:
[x^2 -(2x-3)(x+1)]/x(x+1)

Now we are dividing by a fraction, this means multiply by reciprocal so flip the bottom fraction and multiply it by the top
[(x-2)(x+1)+(x+2)(x-1)]/(x+2)(x+1) * x(x+1)/[x^2 -(2x-3)(x+1)]
there is an (x+1) we can cancel
then expand and add like terms
x(2x^2 -4)/(x+2)(-x^2+x+3)
you can factor out a 2 on top and pull out a negative from bottom leaving
-2x(x^2-2)/(x+2)(x^2-x-3)