Question

can anyone help me get started on this? dh/dt= 0.016(2.5-h) Solve the differential equation to find h in terms of t.

Answer 1

Integrate both side, you get:
\[h(t)=\int\limits_{}^{}0.016(2.5-h)dh\]

Answer 2

Can you do the integration?

Answer 3

h(t)= 0.04t-0.016h^2 ?

Answer 4

Almost there. The second term should be over 2, and don't forget to add a constant (+c).

Answer 5

!!! Rookie mistakes!!! Yes it should. h(t)=0.04t-((0.016h^2)/2)+c
Thankyou AnwarA

Answer 6

We all do that kind of mistakes. You're welcome :)