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Mathematics 19 Online
OpenStudy (anonymous):

Will someone please help me with four problems?

OpenStudy (anonymous):

finding the surface area of these two regular pyramids

OpenStudy (anonymous):

picture 124, 270.00cm is erea base? picture 125, 296.05cm is erea base?

OpenStudy (anonymous):

no those where what i got when i did them and they are wrong

OpenStudy (anonymous):

I want double check 124 the base is square?

OpenStudy (anonymous):

picture 125 the base 5 side ?

OpenStudy (anonymous):

124 base is a triangle. 125 base is 6 sides

OpenStudy (anonymous):

ok, I m not good eyes. I will working this

OpenStudy (anonymous):

h is the high triangle; c is the high of the base of triangle h= √((12)^2-3^2 ) = 11.6 Area triangle= (6*11.6)/2 = 34.8 cm^2 Area for 6 triangles: 34.8*6= 208.8 cm^2 (360°)/6=60 , 60/2 = 30° cos30 = c/12 c = 12cos30 =10.4cm Area base = (base*high*side)/2 (6*10.4*6)/2 = 187.2cm^2 Area base + Area Triangle : 187.2 ^2 +208.8cm^2 = 396cm^2 You check caculator made sure I'm caculater right

OpenStudy (anonymous):

124 I can see which one base, which one high

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