Question

need clarification on solving this equation

Answer 1

which?

Answer 2

\[y ^{3}-10y ^{3 \over 2}+16=0\]

Answer 3

I got y=2 and y=8 so far..I'm not sure if I need to change this to a fraction or what?

Answer 4

Try writing the y^(3/2) in another term, suck as x

Answer 5

if you set x = y^(3/2) you will get x^2-10x+16

Answer 6

ok. Where do I go from here? :/

Answer 7

factor the equation for (x-2) (x-8) so you get x=2 and x=8

Answer 8

and then substitute x = y^(3/2)
and then solve

Answer 9

y^(3/2) = 2
y^(3/2) = 8
y = 2^(2/3)
y = 4

Answer 10

okk gotcha! thanks!