if you travel to work at 30mph and go home by 40 mph, what is the average rate for the entire trip?

Question

anonymous · Answer

I am totally lost, because there is no distance or time given

anonymous · Answer

are you there? I appreciate the help

anonymous · Answer

That's all the problem gives you?

anonymous · Answer

yes, it is why I am so frustated

regan · Answer

(30mph*t1+40mph*t2)/(t1+t2)              which reads total distance over total time
thats all i can think of

anonymous · Answer

yeah, regan's answer looks right

anonymous · Answer

if you aren't given time or distance

regan · Answer

and 30mph*t1=40mph*t2

this may also help

regan · Answer

30mph*t1*2/t1+30mph*t1/40mph

regan · Answer

t1(30*2)          numerator
t1(1+3/4)      denominator

regan · Answer

34.29 mph : )

anonymous · Answer

how'd you get that lol :)

regan · Answer

ok using           30mph*t1=40mph*t2   i said
30mph*t1+30mph*t1=30mph*t1+40mph*t2              in the denominator
and
t1+t2=t1+(30/40)*t1          in the numerator                     
so we have
(t1(30*2))/(t1(1+3/4))                      numerator/denominator             however they both have been written in terms of t1 therefore can cancel to get
30*2/1.75
which equals 34.29

regan · Answer

does that make sense?

anonymous · Answer

yeah it does , thank you so much