Mathematics
16 Online
OpenStudy (anonymous):
(I know its another log question, im obviously not very good at these ha) evaluate the expression: log8(subscript)64^7.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[\log_ab^c = c\log_ab \] and \[log_xx^2 = 2 \]
OpenStudy (anonymous):
ans is 1/14
OpenStudy (anonymous):
how to write these mathematical expressions
OpenStudy (anonymous):
By clicking equation (fun fact: it's not 1/14)
OpenStudy (anonymous):
so would it be 7log8? since 64/8 is 8?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
logx(subscript) \[x ^{m}\] then answer is 1/m sorry guys i'm not good at typing mathematical equations
OpenStudy (anonymous):
and i'm sure it ans is 1/14
OpenStudy (anonymous):
\[\log_864^7 \not= \frac{1}{14} \]
OpenStudy (anonymous):
was i correct? possibly? maybe? ha
OpenStudy (anonymous):
if m is the power to subscript then it comes as 1/m before log
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
hey inewton \[(64)^{7}\]
is subscript
OpenStudy (anonymous):
No it isn't, because that makes no sense.
OpenStudy (anonymous):
the 8 is the subscript
OpenStudy (anonymous):
the 64 is the base, and the 7 is the superscript
OpenStudy (anonymous):
ans is 1/14. question is \[\log_{64^{7}} \]8
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i mean log8 (subcript)\[64^{7}\]
OpenStudy (anonymous):
the question is
\[\log_864^7 = 7\log_864 \]
OpenStudy (anonymous):
ok, thank you very much
OpenStudy (anonymous):
But log_8 64 simplifies further
OpenStudy (anonymous):
it simplifies to just 8, right?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
No
\[\log_ab = c \iff a^c = b\]
So log_8 64 = 2 because 8^2 = 64
OpenStudy (anonymous):
ohhh, ok. thank you! sorry it took so long!
OpenStudy (anonymous):
You're welcome