Question

z^2+8z+16/z^2-100 times z^2-10z/z+4=

Answer 1

i think the answer is 1

Answer 2

(z^2+8z+16/z^2-100)*(z^2-10z/z+4)
= z^2*(z^2-10z/z+4)+8z*(z^2-10z/z+4)+16/z^2-100*(z^2-10z/z+4)
u can finish it right?

Answer 3

lawd it looks even harder lol

Answer 4

z^2*(z^2-10z/z+4) = z^4-10z^3/z+4
8z*(z^2-10z/z+4) = 8z^3-80z^2/z+4
16/z^2-100*(z^2-10z/z+4) = (16z^2/z^2-100)-(160z/(z^2-100)(z+4))
from this is easier

Answer 5

it doesn't nave to be solved simplified

Answer 6

and then what it has to be?

Answer 7

simplified

Answer 8

(z^2+8z+16/z^2-100)*(z^2-10z/z+4)
= z^2*(z^2-10z/z+4)+8z*(z^2-10z/z+4)+16/z^2-100*(z^2-10z/z+4)
=z^4-10z^3/z+4+8z^3-80z^2/z+4+(16z^2/z^2-100)-(160z/(z^2-100)(z+4))
and you simplify by urself from this

Answer 9

The problem statement seems to be:
\[\frac{\left(z^2+8 z+16\right) \left(z^2-10 z\right)}{\left(z^2-100\right) (z+4)} \]
Both of the products in the Numertor can be factored as well as the first product of the Denominator. Factor and then simplify.
\[\frac{(4+z)^2 (-10+z) z}{(-10+z) (10+z) (z+4)}=\frac{z (4+z)}{10+z}\]