Question

Find the following definite integral using the Fundamental Theorem of Calculus.

Answer 1

\[\int\limits_{1}^{3} (1+1/x+3/x^2)dx\]

Answer 2

That's a (1/x^2)

Answer 3

Instead of 3, sorry!

Answer 4

Basically telling you to do F(b)-F(a).

Integrate the function:
{x+ln(x)-1/x} evaluated from 1 to 3. (Plugging in 3 gives F(b), plugging in 1 gives F(a).)

Once you evaluate this you end up getting 8/3+ln(3)