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Mathematics 13 Online
OpenStudy (anonymous):

Solve the inequality x 15 --- + ---- <= 4 4 x+7 for domain

OpenStudy (anonymous):

Multiply both sides by 4(x+7)

OpenStudy (anonymous):

I did but that led me to x^2-9x+172 and that doesnt seem right

OpenStudy (anonymous):

\[x(x+7) + 4(15) \le 4*4(x+7)\] \[\implies x^2 + 7x + 60 \le 16x + 112\] \[\implies x^2 -9x - 52 \le 0\]

OpenStudy (anonymous):

So solve the quadratic for 0 and you have your solutions.

OpenStudy (anonymous):

I got -9 and 13......how do I use those to find the domain?

OpenStudy (anonymous):

that is the domain

OpenStudy (anonymous):

its an inequality theres a different way to solve for the domain

OpenStudy (anonymous):

No, factor it.

OpenStudy (anonymous):

\[(x -13)(x+4) \le 0\]

OpenStudy (anonymous):

That means that one of those two factors must be negative (but not both) for the relation to hold.

OpenStudy (anonymous):

So what values of x will yield a negative in one of either (x-13) or (x+4) but not both.

OpenStudy (anonymous):

between -4 and 13? my options for an answer are A. (-7,-4] U [13, inf) B. (-inf,-7)U(-4,13) C. (-inf,-7]U[-4,13) D. (-inf,-7)U[-4,13] E. (-7,-4)U(13,inf)

OpenStudy (anonymous):

If x is between -4 and 13 (say maybe x=0) we have one positive and one negative, so that seems reasonable.

OpenStudy (anonymous):

We did get rid of a factor of x+7 though when we solved it, so I think your answer is probably D.

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