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Find all the solutions of the Differential Equation dy/dt - 2y^2 = ty^2
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I would say start with separating your variables. (all your y's on one side and the t's on the other)
After that take an integral.
that helps, thanks.
\[y'[t]-2 y^2=t y^2\to y'[t]=t y^2+2 y^2 \] \[\int\limits y'[t] \, dt=\int\limits \left(-2 y^2+t y^2\right) \, dt \] \[y[t]=-2 t y^2+\frac{t^2 y^2}{2} \]
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