Question

x-14 squarerootx +48=0

Answer 1

u=sqrt(x)

so u^2 -14u +48 =0

Answer 2

using factorization method
u^2-12u-4u+48=0
(u-12)(u-4)=0
u=12 or u=4

Answer 3

(u-8)(u-6) =0

Answer 4

the answer has to be solutions

Answer 5

oh u right man

Answer 6

u=6 , u=8

sqrt(x) = 6 --> x = 36

sqrt(x) = 8 --> x= 64

Answer 7

thanks how did you get the answer please tell me how

Answer 8

once u find the values of u, by backward substitution u find x

Answer 9

you simply see how it could fit into a "normal" quadratic form.

if u = sqrt(x)

then u^2 = x right?

So we solve for:

u^2 - 14u +48 = 0 instead; and when we find the values for "u"

we can then determine that value for x; since u = sqrt(x)

when "u" = 6 we get:

6 = sqrt(x); or 6^2 = x, so naturally, x = 36 for this solution

Answer 10

x -14 sqrt(x) +48 = 0
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u^2 - 14 u +48 = 0