Question

a line having a slope of 3/4 passes through the point (-8,4).write the equation of this line in slope intercept form

Answer 1

Use the fomula y-y1=m(x-x1)

Answer 2

it's called the point slope fomula if you want to look it up

Answer 3

equation of a line in point-slope form is\[y-y _{1}=m(x-x _{1})\]
where m is the slope of the line. (x1,y1) is the point which its passing through..
now, plugging in the values you get,
\[y-4=(3/4)(x+8)\]\[=> 4y-16=3x+21 => 4y-3x=21+16 => 4y-3x=37\]

Answer 4

y = (3/4)x + B ; when (x=-8, y=4)

4 = 3(-8)/4 +B

4 = 3(-2) + B

10 = B

y = (3/4)x + 10