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Mathematics 23 Online
OpenStudy (anonymous):

solve the quadratic equation by using the definition of square root and write the solution in radical form.

OpenStudy (anonymous):

\[6y ^{2}=72\]

OpenStudy (anonymous):

Divide by 6 and take the square root.

OpenStudy (anonymous):

i'm stuck at 6y=\[\sqrt{12}\] does it turn into 1 +/- square(2)?

OpenStudy (anonymous):

You should get \[y^2=12\] when you divide both sides by 6.

OpenStudy (anonymous):

ohhh oops, yep yep.

OpenStudy (anonymous):

there are 2 answers though .

OpenStudy (anonymous):

Yes. So then take the square root of both sides....\[y=\pm \sqrt{12}\] Take note of the +/-

OpenStudy (anonymous):

right. ok thanks!

OpenStudy (anonymous):

And then either leave it that way or reduce. You're welcome. :)

OpenStudy (anonymous):

ohh i wonder if it will need to be reduced.. ?

OpenStudy (anonymous):

it says to simplify the solution

OpenStudy (anonymous):

So yes \[y=\pm \sqrt{4x3}\] where x means to multiply. Then the square root of 4 is 2 so we can bring that outside the square root symbol. Thus \[y=\pm2\sqrt{3}\]

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