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solve the quadratic equation by using the definition of square root and write the solution in radical form.
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\[6y ^{2}=72\]
Divide by 6 and take the square root.
i'm stuck at 6y=\[\sqrt{12}\] does it turn into 1 +/- square(2)?
You should get \[y^2=12\] when you divide both sides by 6.
ohhh oops, yep yep.
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there are 2 answers though .
Yes. So then take the square root of both sides....\[y=\pm \sqrt{12}\] Take note of the +/-
right. ok thanks!
And then either leave it that way or reduce. You're welcome. :)
ohh i wonder if it will need to be reduced.. ?
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it says to simplify the solution
So yes \[y=\pm \sqrt{4x3}\] where x means to multiply. Then the square root of 4 is 2 so we can bring that outside the square root symbol. Thus \[y=\pm2\sqrt{3}\]
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