solve the quadratic equation by using the definition of square root and write the solution in radical form.

Question

anonymous · Answer

$$6y ^{2}=72$$

anonymous · Answer

Divide by 6 and take the square root.

anonymous · Answer

i'm stuck at 6y=$$\sqrt{12}$$ does it turn into 1 +/- square(2)?

anonymous · Answer

You should get $$y^2=12$$ when you divide both sides by 6.

anonymous · Answer

ohhh oops, yep yep.

anonymous · Answer

there are 2 answers though .

anonymous · Answer

Yes. So then take the square root of both sides....$$y=\pm \sqrt{12}$$ Take note of the +/-

anonymous · Answer

right. ok thanks!

anonymous · Answer

And then either leave it that way or reduce. You're welcome. :)

anonymous · Answer

ohh i wonder if it will need to be reduced.. ?

anonymous · Answer

it says to simplify the solution

anonymous · Answer

So yes $$y=\pm \sqrt{4x3}$$ where x means to multiply. Then the square root of 4 is 2 so we can bring that outside the square root symbol. Thus $$y=\pm2\sqrt{3}$$