evaluate the indefinite integral.
square root of x^19 times sin(4+x^21/2)dx

Question

evaluate the indefinite integral.
square root of x^19  times sin(4+x^21/2)dx

anonymous · Answer

Are you taking the root of the whole function or just x^19?

anonymous · Answer

just x^19

anonymous · Answer

This ones a beast???
integral sqrt(x^19) sin(4+x^21/2) dx = (2 sqrt(pi) sqrt(x^19) (sin(4) C(x^(21/2)/sqrt(pi))+cos(4) S(x^(21/2)/sqrt(pi))))/(21 x^(19/2))+constant

anonymous · Answer

what does the c and s mean?

anonymous · Answer

They are called Fresnel integrals, said it was a beast to solve, I gather you've not come across them?

anonymous · Answer

no, i havent  learned about them yet

anonymous · Answer

i dont understand where pi came in though, can you explain to me if you have the time?

anonymous · Answer

This is a difficult function to integrate, the pi value is a property of the Fresnel integral process?  Ther is another method using erf??

anonymous · Answer

i got the answer, i understand now. thank you for your help :)