Question

someone please help with this algebra!

Answer 1

i have to solve for x

8/(x^2-1) + 4x/(x-1) + 8/(x+1) = 0

Answer 2

combine fractions by finding common denominator
can you factor x^2 -1 ?

Answer 3

(x+1)(x-1)

Answer 4

good
and the other 2 denominators are factors of that right

Answer 5

yeah but i get lsot after that

Answer 6

ok so our denominator will be (x+1)(x-1) for the 1st fraction nothing changed, 2nd fraction we added (x+1) so add (x+1) to numerator, 3rd fraction we added (x-1) so add (x-1) to numerator

Answer 7

so 8 +4x(x+1)+8(x-1)=0

Answer 8

yes but that is all over (x-1)(x+1)

Answer 9

ohhh
i forgot that step

Answer 10

8+4x+8=0

Answer 11

4x=16 so therefore x=4??

Answer 12

now here is shortcut, because it equals 0 the denominator doesnt matter
0/x = 0
so set numerator equal to 0 and solve for x

Answer 13

did u get 4?

Answer 14

you cant cancel the (x+1) and (x-1) because there is addition on numerator

Answer 15

i have 4x^2 +12x=0

Answer 16

and now im lost again

Answer 17

good so far
try factoring out an x

Answer 18

i mean take an x away from each term
then you will have a product =0
solve for each part setting it equal to 0
you will have 2 answers