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Mathematics 19 Online
OpenStudy (anonymous):

cn someone give me a website with a free online tutor

OpenStudy (anonymous):

Open study

OpenStudy (anonymous):

open study? thts the name of the site

OpenStudy (anonymous):

Yes, there are 27 people available right now that may be able to help you. Just post your question.

OpenStudy (anonymous):

ok\[x/3=30\]

OpenStudy (anonymous):

90

OpenStudy (anonymous):

Multiply both sides by 3.

OpenStudy (anonymous):

which maths paper?

OpenStudy (anonymous):

x/3=30 (3) x/3=30(3) x=90

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

can i go through this study guide with yall because its been a long time since i did any of this

OpenStudy (anonymous):

If you want :)

OpenStudy (anonymous):

\[5x-2=x-9\]

OpenStudy (anonymous):

5x-2=x-9 4x=-7 x=-7/4

OpenStudy (anonymous):

ok thank! can i send a picture of the next problem

OpenStudy (anonymous):

OpenStudy (radar):

Is the circumference 3.4 meters?

OpenStudy (radar):

Is that the diameter of 3.4 meters

OpenStudy (anonymous):

the is question is what is the circumfrence and area of the circle

OpenStudy (radar):

The image is pretty fuzzy. If the diameter is 3.4 meters the circumference is Pi times 3.4. Or 10.68 meters

OpenStudy (anonymous):

:D this is so so much help! should i send a better pic

OpenStudy (radar):

O.K, if that is the diameter (3.4), what would be the radius?

OpenStudy (radar):

Area of a circle is:\[A=\pi \times r ^{2}\] where r equals the radius.

OpenStudy (anonymous):

would tht be half of tht 3.4

OpenStudy (radar):

yes, radius is one half the diameter.

OpenStudy (radar):

I get 1.7 for the radius. What did you come up with?

OpenStudy (anonymous):

im checking now! :)

OpenStudy (anonymous):

got the same

OpenStudy (radar):

Good, use that value for r in the equation for area of a circle (6 post up from this one)

OpenStudy (radar):

\[A=\pi \times (1.7)^{2}\]

OpenStudy (anonymous):

this will give the answer

OpenStudy (radar):

Yes, what did you come up with?

OpenStudy (radar):

I got 9 sq

OpenStudy (radar):

I got 9 sq meters.

OpenStudy (radar):

Did you get something like that?

OpenStudy (anonymous):

yes!!!

OpenStudy (radar):

Good have a nice day.

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

i need help with this next problem! any takers?

OpenStudy (radar):

I can help you (maybe) for one more before I have to leave. I don't mind helping those who are willing to help themselves.

OpenStudy (anonymous):

find missing x

OpenStudy (radar):

The image is really fuzzy. It appears there is a line y=3x-7 and then there appears to be another line intersecting whose equation is y=5x+11. Is this what you see?

OpenStudy (anonymous):

the top of the intersecting line is 5-x=11

OpenStudy (anonymous):

youre right srry

OpenStudy (radar):

O.K. then we could say at that point where they are intersect y=y 5x-11+3x-7 2x=4 x=2 You could plus that in and solve the y point by inspection I can see that y=-1

OpenStudy (radar):

Wait in minute, did you say it is 5x+11, not 5x-11??

OpenStudy (anonymous):

yeah its 5x+11

OpenStudy (anonymous):

it looks to me like a geometry question: 5x+11 + 3x-7 = 180

OpenStudy (radar):

Then it would be 5x+11=3x-7 2x=-18 x=-9

OpenStudy (anonymous):

From the picture it looks like we have a linear pair (a set of angles that make a straight line) so if we add the angles together we get 180 degrees. Setting them equal gives 5x+11 + 3x-7 = 180 so 8x+4=180. 8x = 176 x = 22 degrees

OpenStudy (radar):

Could be, to me it looked like two intersecting lines, all be it one rotated to align it self with the x axis, and the intersection point was to be solved.

OpenStudy (anonymous):

ok so they way tbates did it or the way you did?

OpenStudy (anonymous):

I can see that too, but the cursive l beside the line leads me to think its a linear pairs

OpenStudy (radar):

It appears that Tbates has said this was a geometry question, he is probably rights, as theother questions were about circles etc. so I leave you in his capable hands lol

OpenStudy (anonymous):

If it were lines on a graph I would have wholeheartedly agreed with your solution radar.

OpenStudy (radar):

Yes, I don't see any coordinates etc. I told christy_white, "maybe" I could help her, in this case maybe not. However, christy, is wanting assistance and appears to be sincerely trying, if you can help, please do.

OpenStudy (anonymous):

I'll be around for a bit so post the questions away!

OpenStudy (anonymous):

thanks guys ")

OpenStudy (anonymous):

next question?

OpenStudy (anonymous):

Fire away!

OpenStudy (radar):

Go aheaD Tbates will be back

OpenStudy (anonymous):

ok sending the picture

OpenStudy (anonymous):

if each quadirlateral is a parallelgram then find the value of x y z

OpenStudy (anonymous):

tht two problems

OpenStudy (anonymous):

tht two problems

OpenStudy (anonymous):

If we look at 7 first and specifically z. Again we have a linear pair so: z + 78 = 180

OpenStudy (anonymous):

This means z = 102 in the first problem.

OpenStudy (anonymous):

for x we have a set of parallel lines cut by a transversal so x = 24 (alternate interior angles) http://www.mathsisfun.com/geometry/alternate-interior-angles.html

OpenStudy (anonymous):

Finally all interior angles of a triangle add to 180 so: y + x + 78 = 180 y + 24 + 78 = 180 y + 102 = 180 y = 78

OpenStudy (anonymous):

ok i gotcha!

OpenStudy (anonymous):

On the second one there's a theorem that states opposite angles in a parallelogram are equal so z = 104. Using alternate interior angles x = 32 and y = 44

OpenStudy (anonymous):

Does that make sense?

OpenStudy (anonymous):

had to take my dog out for a min. but im looking over it now

OpenStudy (anonymous):

yeah i understand

OpenStudy (anonymous):

Excellent! Have any more questions?

OpenStudy (anonymous):

ohhh yes i have a whole study guide lol! i can take as much help as anyone is willing to give

OpenStudy (anonymous):

I'll be around, I'm also answering other questions but I'll be helping you out as well.

OpenStudy (anonymous):

the distance btw two points\[( 2, 5)(6, -1)\]

OpenStudy (anonymous):

There is a formula for finding the distance between two points and it's: \[distance = \sqrt{(x _{2}-x _{1})^{2}+(y _{2}-y _{1})^{2}}\] \[\sqrt{(5-2)^{2}+(-1-6)^{2}}\] \[\sqrt{(3)^{2}+(-7)^{2}}\] \[\sqrt{9 + 47}\] √56 = 7.48

OpenStudy (anonymous):

oops I meant √58 = 7.62

OpenStudy (anonymous):

all done?

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