cn someone give me a website with a free online tutor
Open study
open study? thts the name of the site
Yes, there are 27 people available right now that may be able to help you. Just post your question.
ok\[x/3=30\]
90
Multiply both sides by 3.
which maths paper?
x/3=30 (3) x/3=30(3) x=90
thank you
can i go through this study guide with yall because its been a long time since i did any of this
If you want :)
\[5x-2=x-9\]
5x-2=x-9 4x=-7 x=-7/4
ok thank! can i send a picture of the next problem
Is the circumference 3.4 meters?
Is that the diameter of 3.4 meters
the is question is what is the circumfrence and area of the circle
The image is pretty fuzzy. If the diameter is 3.4 meters the circumference is Pi times 3.4. Or 10.68 meters
:D this is so so much help! should i send a better pic
O.K, if that is the diameter (3.4), what would be the radius?
Area of a circle is:\[A=\pi \times r ^{2}\] where r equals the radius.
would tht be half of tht 3.4
yes, radius is one half the diameter.
I get 1.7 for the radius. What did you come up with?
im checking now! :)
got the same
Good, use that value for r in the equation for area of a circle (6 post up from this one)
\[A=\pi \times (1.7)^{2}\]
this will give the answer
Yes, what did you come up with?
I got 9 sq
I got 9 sq meters.
Did you get something like that?
yes!!!
Good have a nice day.
thank you
i need help with this next problem! any takers?
I can help you (maybe) for one more before I have to leave. I don't mind helping those who are willing to help themselves.
find missing x
The image is really fuzzy. It appears there is a line y=3x-7 and then there appears to be another line intersecting whose equation is y=5x+11. Is this what you see?
the top of the intersecting line is 5-x=11
youre right srry
O.K. then we could say at that point where they are intersect y=y 5x-11+3x-7 2x=4 x=2 You could plus that in and solve the y point by inspection I can see that y=-1
Wait in minute, did you say it is 5x+11, not 5x-11??
yeah its 5x+11
it looks to me like a geometry question: 5x+11 + 3x-7 = 180
Then it would be 5x+11=3x-7 2x=-18 x=-9
From the picture it looks like we have a linear pair (a set of angles that make a straight line) so if we add the angles together we get 180 degrees. Setting them equal gives 5x+11 + 3x-7 = 180 so 8x+4=180. 8x = 176 x = 22 degrees
Could be, to me it looked like two intersecting lines, all be it one rotated to align it self with the x axis, and the intersection point was to be solved.
ok so they way tbates did it or the way you did?
I can see that too, but the cursive l beside the line leads me to think its a linear pairs
It appears that Tbates has said this was a geometry question, he is probably rights, as theother questions were about circles etc. so I leave you in his capable hands lol
If it were lines on a graph I would have wholeheartedly agreed with your solution radar.
Yes, I don't see any coordinates etc. I told christy_white, "maybe" I could help her, in this case maybe not. However, christy, is wanting assistance and appears to be sincerely trying, if you can help, please do.
I'll be around for a bit so post the questions away!
thanks guys ")
next question?
Fire away!
Go aheaD Tbates will be back
ok sending the picture
if each quadirlateral is a parallelgram then find the value of x y z
tht two problems
tht two problems
If we look at 7 first and specifically z. Again we have a linear pair so: z + 78 = 180
This means z = 102 in the first problem.
for x we have a set of parallel lines cut by a transversal so x = 24 (alternate interior angles) http://www.mathsisfun.com/geometry/alternate-interior-angles.html
Finally all interior angles of a triangle add to 180 so: y + x + 78 = 180 y + 24 + 78 = 180 y + 102 = 180 y = 78
ok i gotcha!
On the second one there's a theorem that states opposite angles in a parallelogram are equal so z = 104. Using alternate interior angles x = 32 and y = 44
Does that make sense?
had to take my dog out for a min. but im looking over it now
yeah i understand
Excellent! Have any more questions?
ohhh yes i have a whole study guide lol! i can take as much help as anyone is willing to give
I'll be around, I'm also answering other questions but I'll be helping you out as well.
the distance btw two points\[( 2, 5)(6, -1)\]
There is a formula for finding the distance between two points and it's: \[distance = \sqrt{(x _{2}-x _{1})^{2}+(y _{2}-y _{1})^{2}}\] \[\sqrt{(5-2)^{2}+(-1-6)^{2}}\] \[\sqrt{(3)^{2}+(-7)^{2}}\] \[\sqrt{9 + 47}\] √56 = 7.48
oops I meant √58 = 7.62
all done?
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