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Mathematics 15 Online
OpenStudy (anonymous):

wats 2 +2

OpenStudy (anonymous):

Hmm maybe like 3+1 or something. I dunno

OpenStudy (anonymous):

\[2 +2 =5+e^{i\pi}\]

OpenStudy (anonymous):

Lol.. You want the questioner to kill himself?

OpenStudy (anonymous):

or better yet \[4 = e^{i\pi*n}\]\[n = (2n\pi-2ilog(2))/{\pi}\] for \[n \in \mathbb{Z} \] where log(n) is the natural log

OpenStudy (anonymous):

\[ 4 = e^{i*pi*x}\] \[x =(2n\pi - 2ilog(2))/\pi \] for \[n \in \mathbb{Z} \] rather

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