Caffenie leaces the body at a rate of 15.6% each hou. your first cup of coffee in the morning has 100 mg of caffenie How long will it take before you have 50 mg of that caffenie in your body and how long will it take before you have 25 mg of caffenine in your body
Y=-.156x + 100. Put in each value for x and solve.
I'm sorry, not for x, for y and solve for x.
Y=-.156x + 100. Put in each value for y and solve.
k i got .00208 and .00312
ia itright
torch
Actually you have to use k=Ce^rt. C=.5 K=50 r=-.156 Solve for t.
ok so what doo i do first
after plugiign in the number s
can u show me please so i will know
can u show me please so i will know
K first divide by the constant. Then natural log both sides and divide by the other constant and you get the answer you had first.
.0028 and .0032
can u show me step by step so I know how to ddo it the next time
Alright do you have an answer key? Like what you're supposed to get?
no where
Well you said the natural log answer a while ago
Oh jk that was a different one.
yeah so can u please show me step by step on how to solve this problem
please
please
K hang on. I'll write it out for you but it'll take a bit. My iPad hates the typing in this.
not to be rude but cn u hurry up please
Alright, an easy way to think about it is to use a proportion. -.156=x/amount of caffeine. For example for the first one, you put in 100 and then you get 84.4. Basically you found the percentage of the amount of caffeine and subtracted it. You do that 4 times to get to 50, so that's 4 hours. Fir the second one, you do the same thing, and just keep going. You get 8 hours. Sorry it took so long, I was busy.
Good nuff?
yes thank you
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