What is the quadratic equation that goes through the points (-8,0) and (4,5) to find the a,b,c of the parabola
You only have three points, so you'll end up with an infinite number of parabolas. Were you only given two points?
Two points, I meant to say.
Yes, so i guess i need to find the vertex, which would then give me 3 points right?
Well, two points won't be enough. You have two linear equations given your points: \[64a-8b+c=0\]and\[16a+4b+c=5\] You need three linearly independent equations for a unique solution (a, b, c).
So can the just be a quadratic equation with 2 points? Or to do anything with this problem would I need 3 points?
You can get *something* out of it, though you won't get something unique. You'll get an infinite number of possibilities. You can solve those two equations to get\[b=4a+\frac{5}{12}\]and then sub. that back to find \[c=\frac{10}{3}-32a\]but this will be as far as you can get. You now have the choice of any 'a' you wish, and the equations for b and c will give you a quadratic that will contain your points.
Okay thanks!
No probs. Just check those equations. I did them on-the-fly.
Join our real-time social learning platform and learn together with your friends!