Question

Can someone please Help me with college algebra 2 ?

Answer 1

ok

Answer 2

\[\sqrt[4]{32y^13}\]

Answer 3

32 = 2 x 2 x 2 x 2

Answer 4

i left out one 2

Answer 5

its y raised to the 13th

Answer 6

im guessing im factoring it?

Answer 7

are you trying to solve for y?

Answer 8

no i think you are trying to simplify the expression

Answer 9

i was using prime factorization

Answer 10

right simplify

Answer 11

so you have 32 factored to 2^5, so take away 16 from inside the radical and leave in one 2
as for y, you have y^3 outside the radical and one y inside, since (y^3)^4 * y = y^13

Answer 12

im pretty sure it is 2y^3*radical4(2y)

Answer 13

so its 32^(1/4)*y^(13/4)*3^(1/4)

Answer 14

its a 4 outside the radical and 32y^13 on the inside

Answer 15

Factor completely:
6b^2+4a-8b-3ab

Answer 16

wait, ok your previous expression was messed up, can you re type it?