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Mathematics 23 Online
OpenStudy (anonymous):

Can someone help me in u substitution i forgot how to do that.

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Post a problem

OpenStudy (anonymous):

What's the problem?

OpenStudy (anonymous):

If the substitution \[u=\sqrt{x-1}\] is made, the integral \[\int\limits_{2}^{5} \sqrt{x-1}\div x dx=\]

OpenStudy (anonymous):

u=\[\sqrt{x-1}\]

OpenStudy (anonymous):

so du= \[1\div(2(\sqrt{x-1})\]

OpenStudy (anonymous):

try it from there

OpenStudy (anonymous):

ok i've got that so far

OpenStudy (anonymous):

i need to find x too right?

OpenStudy (anonymous):

no because u is equal to that part of the denominator

OpenStudy (anonymous):

so you have, 2\[2\int\limits_{}^{}u^2/(u^2+1)\]

OpenStudy (anonymous):

ok i don't get how you got that.

OpenStudy (anonymous):

go there but don't forget the domain of integration

OpenStudy (anonymous):

thanks

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