Question

29g of copper pellets are removed from a 300 Celsius oven and immediately dropped into 100 mL of water at 22 Celcius in an insulated cup.

What will the new water temperature be?

Answer 1

Q=m*c*delta(T) simple

Answer 2

That's not quite right. Actually it's:
\[\Delta Q = m c \Delta T\]
So you know, cause of the conservation of energy, that the quantity of heat remains the same.

So:
\[c_1 * m_1 * (T_1 - T_*) = c_2 * m_2 * (T_* - T_2)\]
when plugging in 0.39 for copper and 4.19 i get 29°C for the resulting temperature...