Hey can you help with this one: express in simplest form: 3/ the square root of 3a^2b. In other words, 3 is the numerator and the denominator is the square root of 3a^2b
\[\sqrt{3}*a ^{-b}\]
can you tell me what you did to get there?
I can't figure out how to get there. I thought maybe to multiply top and bottom of fraction by square root of 3a^2b. Does that sound right?
yeah that sounds correct to me
so then I end up with 3*sq rt of 3a^2b on the top and 3a^2b in the denominator. but then what do I do next??
the 3s will cancel and your left with sqrt of 3a^2b / a^2 b
OK i've got you so far. thanks. But then what?
I don't know what to do with numbers when they are in the square root.
it cant be simplified anymore
oh really? someone else gave me the answer sq rt 3 * a^-b not sure how they got it. It was inik
you cant just cancel out the denominator like that because because the numerator is under a sq rt
ok so the numerator must stay as is? And so the problem cannot be simplified any further?
thats what i think.
OK thanks!
glad i could help
this math stuff can make a person crazy
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