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Mathematics 17 Online
OpenStudy (anonymous):

I really need help with this..I need to rewrite this to a single logarithm with coefficient one 1/2logx-1/3logy-2logz

OpenStudy (anonymous):

log sq.rt x-1 / log y / log z^2

OpenStudy (anonymous):

I didnt think you could write all 3 in a divison, i got to : log x^1/2-logy^1/3-logz^2 and now im stuck

OpenStudy (anonymous):

i know the minus goes to division but i dont believe you can do all three dividing eachother

OpenStudy (anonymous):

then multiply by reciprocal or sth?

OpenStudy (anonymous):

1/2logx-1/3logy-2logz =log [x^(1/2)] - log [y^(1/3)] - log [z^2] =log [ sqrt(x) / (cbrt(y) z^2) ]

OpenStudy (anonymous):

what is cbrt?

OpenStudy (anonymous):

cube root

OpenStudy (anonymous):

cubic root

OpenStudy (anonymous):

cube root :P

OpenStudy (anonymous):

ok great thankyou both!

OpenStudy (anonymous):

my pleasure :)

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