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I really need help with this..I need to rewrite this to a single logarithm with coefficient one 1/2logx-1/3logy-2logz
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log sq.rt x-1 / log y / log z^2
I didnt think you could write all 3 in a divison, i got to : log x^1/2-logy^1/3-logz^2 and now im stuck
i know the minus goes to division but i dont believe you can do all three dividing eachother
then multiply by reciprocal or sth?
1/2logx-1/3logy-2logz =log [x^(1/2)] - log [y^(1/3)] - log [z^2] =log [ sqrt(x) / (cbrt(y) z^2) ]
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what is cbrt?
cube root
cubic root
cube root :P
ok great thankyou both!
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my pleasure :)
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