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int_{}^{?}e ^{4t}sin3t
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integrate \[\int\limits_{}^{?}e ^{4t}\sin3t\]
\[\int\limits e ^{4t} \sin3t dt ?\]
can be solved by integration by parts
\[e ^{4t} -\cos3t/3 -\int\limits -\cos3t/3.e ^{4t} 4 dt\]
\[\cos3t.e ^{4t} /3 +(4/3)\int\limits e ^{4t} \cos 3t d t\]
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oh i missed the negative sign -(cos3t.e4t)/3+(4/3)∫e4tcos3tdt
yea its by using the formula
Yeah, you will never finish integrating but you will get a multiple of the original integral eventually...so you move it to the other side of the equation and combine with the original integral and, shazam!, you are done.
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