(h(t)=-16t^2+vt+c where h is the approximate height in ft t is the time in motion in seconds v is the initial upward velocity in ft per second and c is the initial height in ft)

A baseball player hits a pitched ball when it is 4ft above the ground the initial upward velocity is 80ft/s how long will it take for the ball to hit the ground???

Question

(h(t)=-16t^2+vt+c where h is the approximate height in ft t is the time in motion in seconds v is the initial upward velocity in ft per second and c is the initial height in ft)

A baseball player hits a pitched ball when it is 4ft above the ground the initial upward velocity is 80ft/s how long will it take for the ball to hit the ground???

anonymous · Answer

since H(t) is the height of the ball at a certain time, and you want to know the time at height 0 (when it hits the ground), set H(t) to 0. Then plug in the known values and solve for t

anonymous · Answer

u trying 2 make dat seem easy but it wont  work try it

anonymous · Answer

okay, so we set the left side to 0, and plug in the values we know: V=80, C= 4. your equation at this point should be -16t^2+80t+4=0. Now all thats left is to isolate t by simplifying the expression and then solving. Hope this helps

anonymous · Answer

i simplified and got 0=-4t^2+20t+1  do i figure out wat the time is

anonymous · Answer

how