When a certain spring is expanded 6 centimeters from its natural position and held fixed, the force necessary to hold it is 1200 dynes. Find the work W required to stretch the spring an additional 6 centimeters.

Question

anonymous · Answer

What's the spring constant?

anonymous · Answer

Never mind you can calculate it with the given information

anonymous · Answer

I tried $$\int\limits_{0}^{6} (k x)dx=1200 $$
$$k*(6^2/2)=1200  $$ 
So that k=200/3

anonymous · Answer

The force on a spring is
F= k (d1 - d0)
we say d0=0 and d1 is 6 cm 
so 1200= k * 6
200= k

F= k ( d1- d0) 
where d1 is 12 cm and d0 is 6 cm
F to stretch additional 6 cm is 200* 6
F= 1200
where work is F* change in distance
we changed the distance by 6 cm 
so it should be 1200 * 6= 7200

anonymous · Answer

I solved this with the knowledge I have in physics so this might not be what your teacher wants to see.

anonymous · Answer

Thank you I'll try it out

anonymous · Answer

Physics is a useful tool in mathematics: it explains a lot; math concentrates on the calculations.