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Mathematics 15 Online
OpenStudy (anonymous):

Need help.....

OpenStudy (anonymous):

OpenStudy (anonymous):

Get the second function in respect to y like the first one and graph them.

OpenStudy (anonymous):

Since you have to create a rectangle with another point and the two functions you can predict that the functions will be perpendicular to each other

OpenStudy (anonymous):

are you having trouble graphing the functions?

OpenStudy (anonymous):

is slope -2 yeah

OpenStudy (anonymous):

\[2y + x= 2\] \[2y + x - x= 2 -x\] \[2y = 2 -x \] \[2y/2 = (2 -x)/2 \] \[y = 2/2-x/2\] \[y = 1-(x/2)\]

OpenStudy (anonymous):

perpendicular functions have inverse slopes.

OpenStudy (anonymous):

is it something like this lol

OpenStudy (anonymous):

that's a triangle not a rectangle -.-

OpenStudy (anonymous):

my bad i thought it said triangle lol

OpenStudy (anonymous):

let me try again

OpenStudy (anonymous):

idk

OpenStudy (anonymous):

nah i did it wrong try again

OpenStudy (anonymous):

this one i hope

OpenStudy (anonymous):

OpenStudy (anonymous):

i give up thats not right either dont look right i did -3 instead of 3

OpenStudy (anonymous):

OpenStudy (anonymous):

both are wrong. The second one shows that they are parallel but they are perpendicular while the first one shows that x=a and y=b where both a and b are constants which is not the case here. If you are having trouble graphing try plotting some points try plotting some points make a table if X= 1,0,-1 what is y? do this for both

OpenStudy (anonymous):

If you plug in X=0 what do you get in function 1 and 2?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

show me your work

OpenStudy (anonymous):

do i subtract 2x from both sides?

OpenStudy (anonymous):

no Im asking you what happens when X=0

OpenStudy (anonymous):

idk im lost

OpenStudy (anonymous):

Are you taking pre-algebra?

OpenStudy (anonymous):

algebra 1

OpenStudy (anonymous):

if you have y= 2x + 1 and you plug in 0 for x what does y equal?

OpenStudy (anonymous):

3

OpenStudy (anonymous):

why is that?

OpenStudy (anonymous):

is 2 * x or 2+x?

OpenStudy (anonymous):

2+0=2+1=3

OpenStudy (anonymous):

where did you get that 2+0 from?

OpenStudy (anonymous):

its y = (2*x) + 1 solve that when you have x=0

OpenStudy (anonymous):

answr 1

OpenStudy (anonymous):

Do the same for the other function

OpenStudy (anonymous):

answr 2

OpenStudy (anonymous):

that's wrong please show work to see where you went wrong

OpenStudy (anonymous):

2*0+0=2

OpenStudy (anonymous):

no you said y= o in that equation please look above in the equation I have and solve for y when x=0

OpenStudy (anonymous):

is it 1

OpenStudy (anonymous):

point (1,3)

OpenStudy (anonymous):

Nope wrong. Sorry man I can't help you

OpenStudy (anonymous):

ok im a girl thanks anyway

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