Question

solve the problem exactly:
log(2x+7)=1+log(x-1

Answer 1

make both sides as power of 10
\[10^{\log_{}2x+7 }=10^{1+\log_{}x-1 }\]
this will cancel the logs
2x+7 = 10(x-1)
-8x = -17
x = 17/8

Answer 2

thanks :)