Find the work done by the force field F that is not conservative. The distance is between two points. How would you approach this problem since the Fundamental Rules of Calculus do no apply.
integrate along the path F.dr
Don't you need to Integrate?
ya
vector integral
vector is <z,x,y> how would you do it when the path is a straight line?
give us the question..well see
between point (3,0,0) to point (0,pi/2,3)
when the path between those two points is a straight line
I'm having trouble knowing what to do when it's path dependent.
whats the force?
F(x,y,z)= z i + x j + y k
gotcha
so dr is the distance between the two points?
first write the eqn of a line in cartesian form like x=3+3k y=k(pi)/2 z=3k
parametric representation of the line segment right?
the work done is F.dr which is <zdx, xdy, ydz> right
sorry write y=-k(pi)/2 and z = -3k
got it till here??
Kinda it's just hard to remember how to find the parametric equations of a line
no bt ive written em down fr u nw
kk so use dot product of the vector with dr right?
so you just replace x y z with the parametric equations right?
so here goes dot prod gives zdx + xdy + ydz for zdx write (-3k)(dx) (-3k)(3dk)
now integrate this -9k^2 dk from k =0 to k=-1
coz k=-1 gives u ur final point
got it?
yup
now similarly compute it for xdy and ydz and then add all three/
got it?
Yes so my area of integration is going to change because I reperamatize right?
yes integrate all three frm 0 to -1
bcoz remmbr on ur line k=0 gives the initial pt and k=-1 givs d final pt...so as our integrating variable is k, we use the lim its fr k
that should do it i spose
yup my book shows it but in two dimensions....
js get the answer and tally it..its complicated enough...ur book mightve represented it in 2d..fr me dis is d way i thot dis cld be done
wt hapnd??
nothing I got the answer
Join our real-time social learning platform and learn together with your friends!