Question

Find Dy/dx if y= cos(xy)

Answer 1

implicit :)

Answer 2

dy/dx= -sin(xy)[1+dy/dx]

Answer 3

-(y+xy')sin(xy)

Answer 4

dy/dx +sin(xy)dy/dx=-sin(xy)

Answer 5

dy/dx[1+sin(xy)] = -sin(xy)

Answer 6

dy/dx=-sin(xy)
---------
[1+sin(xy)]

Answer 7

y'
------ = -sin(xy)
y+xy'

y+xy'
---- = -csc(xy)
y'

Answer 8

(y/y') + (xy'/y') = -csc(xy)

(y/y') +x = -csc(xy)

y/y' = -csc(xy) -x

y' = y/(-csc(xy))-x

Answer 9

amistre ...where m i wrong??

Answer 10

y' = y -y sin(xy)
----------- = ------------
-1/sin(xy) -x x sin(xy) +1

Answer 11

oh i got it...in the very first step i missed y

Answer 12

lol..... and where if any did i mess it up ;)

Answer 13

i was just trying to match the answer...u know it is much easier to solve a sum than to point out a mistake :D

Answer 14

;)

Answer 15

dy/dx= -sin(xy)[y+xdy/dx]

Answer 16

dy/dx +xsin(xy)dy/dx=-ysin(xy)
dy/dx[1+xsin(xy)] = -ysin(xy)
-ysin(xy)
dy/dx= ---------
[1+xsin(xy)]

Answer 17

thanks