Question

Could someone tell me if my answer was correct? I will attach the equation and available answers in a comment! Its just a algebra question but im evidently unable to focus rite now >.<

Answer 1

here :)

Answer 2

Which one is the question?

Answer 3

the one that says "ok" ^_^

Answer 4

I see.

Answer 5

The process is confusing me im pretty sure this is one of the lessons that i missed :P

Answer 6

So the question is to simplify:
\[{4 \over m+2}+{2 \over m-2}?\]

Answer 7

The m + 2 and m - 2 is confusing me :P And it says to Add and Simplify.

Answer 8

Good. First, what is the LCM of (m+2) and (m-2).

Answer 9

Thats the part that was confusing me ^_^ lol

Answer 10

Haha I see. Do (m+2) and (m-2) have any common factors?

Answer 11

Yep lol >.< i think urghh i should of paid attention :P and i just didnt know how to write it bc of the - and + signs >.< lol

Answer 12

Well they don't have a common factor, and because of that the LCM of them is their multiplication.

Answer 13

Ahhhhhh alright i get it so far. ^_^

Answer 14

so (m+2)(m-2)=m^2-4. That's would be our LCM.

Answer 15

That's good. Now, we have to apply this to our equation.

Answer 16

expression*

Answer 17

ohhhh haha wow ya bc since they dont have a common factors u'd multiply them together. alright.

Answer 18

Exactly.

Answer 19

That means, we will multiply the first term (top and bottom) by (m-2). and multiply the second term (top and bottom by (m+2).

Answer 20

Does that make sense?

Answer 21

Yes so far so good so then the answer would be the "ya" one? lol like my labels? :D

Answer 22

>.< i think... :P

Answer 23

\[{4 \over m+2}+{2 \over m-2}={4(m-2) \over m^2-4}+{2(m+2) \over m^2-4}={4m-8+2m+4 \over m^2-4}={6m-4 \over m^2-4}\]

Answer 24

OR as in the choices:
\[{6m-4 \over (m+2)(m-2)}\]

Answer 25

WOOOOOOOOOOOOO!!!! so i was rite huh?!?! YAY YAY YAY!!

Answer 26

lol ^_^

Answer 27

Haha Yeah you were :)

Answer 28

:) Thanks, helped my bunches! :D

Answer 29

np

Answer 30

Oh! and do you think you could help me on part of this other question? :) plesss? lol

Answer 31

This is it. do u think u will help meh? :)

Answer 32

so ok is the original expression?

Answer 33

You make strange names? :P

Answer 34

My question is about the denominators again so would there be common factors? >.< i got confused again :P lol and ya i am making strange names ^^

Answer 35

The same first question again, do they have common factors?

Answer 36

And yea this is the original expression .. pretty sure lol

Answer 37

and i thought they did >.< like since 3x can go into 6x.. but then i got lost arghh

Answer 38

Okay can you factor any of the two denominators?

Answer 39

No i dont think so

Answer 40

Wait which version of factoring? >.<

Answer 41

3x+5 can't be factored..
(6x+10)=2(3x+5).. right?

Answer 42

Right.

Answer 43

Okay now your LCD should be each one of the factor to be taken only one. the factors we have are (3x+5) and 2. so our LCD would 2(3x+5).

Answer 44

I don't think that was clear enough, was it?

Answer 45

Not really im sitting here repeating it over in my head going wth.... ^_^

Answer 46

LOL

Answer 47

Well, you can see that (3x+5) occur in both denominators. right?

Answer 48

after factorization*

Answer 49

Yep i see that.

Answer 50

\[{2 \over 3x+5}-{1 \over 6x+10}={2 \over 3x+5}-{1 \over 2(3x+10)}\] Right?

Answer 51

Now list all factors in both denominators.

Answer 52

I mean 2(3x+5) :)

Answer 53

Ahhhh so then i see why you would do that. But couldnt you just multiply the 3x + 5 expression by 2 and then subtract?

Answer 54

the two equations with the same denominator i mean ^^

Answer 55

Yes you could, but then you have to simplify after that.

Answer 56

that wouldn't be the simplest form.

Answer 57

Ahhh rite, ^_^ ok then go on lol

Answer 58

Well you're saying that you multiply the (3x+5) by 2, that's right. And that's what I was trying to say when I said that 2(3x+5) is the LCD. So then we keep the 6x+10 and multiply the (3x+5) term (top and bottom) by 2.

Answer 59

:)

Answer 60

ohh so the answer would be B haha wow i rly need to stop doubting myself argh :P

Answer 61

LOL thanks for the help! AGAIN ^_^

Answer 62

But you know why we can do that. That's because the denominator of the second term is nothing but 2 times the denominator of the first term.

Answer 63

AnwarA, how did you make the rational expression look like that ?

Answer 64

It's 2(3x+5).. just typo :P

Answer 65

all I can do is\[{a+bi}/{10a-c}\]

Answer 66

how did you make it go under a long bar ?

Answer 67

lol think person means like how do u ya long bar ^^

Answer 68

Oh.. {a+bi over 10a=c}

Answer 69

And hello yuki.

Answer 70

:)

Answer 71

>.< i will never understand computer tech/ math peoples smartness :P

Answer 72

haha. I think I am the only one who does it this way :P

Answer 73

\[\sqrt(b^2-4ac) \over 2a\]

Answer 74

that is sooo cooooool !! I am goint to use it from now on, thanks!

Answer 75

LOL obviously not anymore!! :D and i see someone ik viewing the question but he isnt in our meeting place!! >:P lol (inside joke cant rly explain it ^^)

Answer 76

\[{\sqrt{b^2-4ac} \over 2a} \]
:P

Answer 77

can you do "plus or minus" as well ?

Answer 78

Haha

Answer 79

>.< smart people arg lol

Answer 80

Yep anything

Answer 81

\[{-b \pm \sqrt{b^2-4ac} \over 2a}\]

Answer 82

how did you make the sqrt top part long ?!
I have so much to learn lol

Answer 83

Haha try that yourself :P

Answer 84

is there a place that have all of that written down ?

Answer 85

*sigh* so much to learn to little time lmao im jk :)

Answer 86

just use {}, with anything that you want to make long :)

Answer 87

\[\sqrt{10x+b}\]

Answer 88

Hah, i think its funnay how i have no idea how the heck u guys are doing that ^^

Answer 89

\[e^{ANWAR}={1 \over \sqrt{yuki}^{dolly}}\] :P that does not mean anything by the way

Answer 90

\[\int\limits _{a,b}_{b,a}\]

Answer 91

lol im above yuki hee hee!!!!

Answer 92

I am in the top, that's what matters :D

Answer 93

\[\ln(\ln (x)) = 0\]

Answer 94

:P looks more like im the glue that holds everything together mwuahahaha!!!

Answer 95

take ln of both sides to bring me down :(