Question

Can someone help with with a question please?
>Using Quadratic Formula and/or Substitution solve:
((t^2) -7) - 3((t^2) -7) + 2 = 0

(t^2) = T to the second power

Answer 1

expand the problem and see what it gets you

Answer 2

heres what i got so far. : Using the quadratic formula:
(Substitution) U = ((t^2) - 7) ==> u^2 - 3u + 2 ==> Quadratic Formula ==> 3 +- sqrt{9+8 ==> Answer that i got was : 3 (plus or minus) sqrt{ 17} divided by 2

Answer 3

Is this correct?

Answer 4

not according to the question you posted; is the original typoed?

Answer 5

hmm shoot yes it is, im so sorry. its : ((t^2) - 7)^2 - 3((t^2) -7) + 2 = 0

Answer 6

ok..... your quadratic formula has issues to it; you seem to have forgotten to /2a

Answer 7

Um at the end of my answer i stated "Divided by 2"

Answer 8

i see it; its was lost in the formating lol

Answer 9

sqrt(b^2 -4(a)(c))...youve got a +4(a)(c)

Answer 10

3 sqrt[9-8]
--- +- --------
2 2

Answer 11

Wow, i cant believe i made that mistake.

Answer 12

your answers should end up as :

t^2 -7 = 1 and t^2 -7 = 2

Answer 13

you slow typing ? :)

Answer 14

May i ask, after the 3+- sqrt { 9-8} = 3+- sqrt {1}
-----------
2
so ==> it'd be 3+ 1 \2 || 3-1 \2?

Answer 15

im at work sorry lol

Answer 16

lucky you; i aint got a job ...

Answer 17

yes; as long as i see it correctly; you did that right

Answer 18

:D thanks for your help. And oh on that note, ill be unemployed by the end of this month. :( Work place is closing shop.

----- Quick confirmation: final answer = final answers = 2 and 1 correct?

Answer 19

the final answer is to solve for t....not u :)

final answers should be:


+- 2sqrt(2) and +-3

Answer 20

ah... if i may, how did you arrive at that?

Answer 21

u = 1 = t^2-7 u=2=t^2-7
8=t^2 9=t^2
+-2sqrt(2) +-3

Answer 22

:D thanks man. i get it (mostly :P) this sites awesome :) i think i might post here for help some other time

Answer 23

:) good luck