Question

How does one parametrize the function z^2=sqrt(x^2+y^2)/3?

Answer 1

BTW its a Conic frustum

Answer 2

Swing z^2 on the other side and find derivative

Answer 3

actually I typed it wrong its z=sqrt(x^2+y^2)3

Answer 4

ugh z=sqrt(x^2+y^2)/3

Answer 5

find derivative, find magnitude of derivative

Answer 6

The derivative with respect to what?

Answer 7

This function need to be a vector, so partial fractions to get <x,y,z>