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Mathematics 53 Online
OpenStudy (anonymous):

How does one parametrize the function z^2=sqrt(x^2+y^2)/3?

OpenStudy (anonymous):

BTW its a Conic frustum

OpenStudy (anonymous):

Swing z^2 on the other side and find derivative

OpenStudy (anonymous):

actually I typed it wrong its z=sqrt(x^2+y^2)3

OpenStudy (anonymous):

ugh z=sqrt(x^2+y^2)/3

OpenStudy (anonymous):

find derivative, find magnitude of derivative

OpenStudy (anonymous):

The derivative with respect to what?

OpenStudy (anonymous):

This function need to be a vector, so partial fractions to get <x,y,z>

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