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OpenStudy (anonymous):
How does one parametrize the function z^2=sqrt(x^2+y^2)/3?
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OpenStudy (anonymous):
BTW its a Conic frustum
OpenStudy (anonymous):
Swing z^2 on the other side and find derivative
OpenStudy (anonymous):
actually I typed it wrong its z=sqrt(x^2+y^2)3
OpenStudy (anonymous):
ugh z=sqrt(x^2+y^2)/3
OpenStudy (anonymous):
find derivative, find magnitude of derivative
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OpenStudy (anonymous):
The derivative with respect to what?
OpenStudy (anonymous):
This function need to be a vector, so partial fractions to get <x,y,z>
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