if a rectangular area is 64 m^2 and a rope is strung from one corner to the midpoint of one of the two more distant sides, what is the minimum distance of the rope?
A. 32m
B. 16m
C. 6 m
D. 4 m

Question

anonymous · Answer

use pythag theorom

anonymous · Answer

can someone take a look at mine

anonymous · Answer

prettychicka45 please go away

anonymous · Answer

Let:   L = lenght
        H = Height
        Ar = Area of rectangle
        At = Area of Triangle
        d = rope distance

from rectangular area:
         L*H = Ar
         L*H = 64

The rope will form a triangle with dimensions:
        Height = h/2
        Length = l

so the area of the triangle is:
        At = (l*(h/2))/2

and we also know that At = (1/3)Ar  . From these two equations you can solve for h and l

With h and l values, use the pythag theorom to find d:
$$d = \sqrt{L^{2} + (w/2)^{2}} $$

anonymous · Answer

but how would I find the minimum?

anonymous · Answer

the minimun is whatever yu found for d