Mathematics
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OpenStudy (anonymous):
find the integral S (x/6 + 6/x) dx
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OpenStudy (anonymous):
You can break apart the integral
OpenStudy (anonymous):
\[\int\limits_{}^{}({x \over 6}+{6 \over x})dx={x^2 \over 12}+6\ln \left| x \right|+c={x^2 \over 12}+\ln (x^6) +c\]
OpenStudy (anonymous):
how did u get x^12/12?
OpenStudy (anonymous):
It's x^2/12. Because when you integration of x is x^2/2, then multiply this by 1/6, you get x^2/12.
OpenStudy (anonymous):
hey, anwarA. How did yu do for the fraction to appear like that ?
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OpenStudy (anonymous):
How much would you pay for that? :P
OpenStudy (amistre64):
frac{}{}
OpenStudy (anonymous):
i'll givu a medal haha
OpenStudy (anonymous):
@amistre64: he/she asked me >.<
OpenStudy (amistre64):
lol....then answer ;) if you know how lol
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OpenStudy (anonymous):
oh thanks amistre \[frac{1}{2}\]
OpenStudy (anonymous):
phail lol
OpenStudy (amistre64):
i left out that part where you do it in the....
OpenStudy (anonymous):
I'll tell you another way, a better way. "{something over something}"
OpenStudy (anonymous):
using the "equation" feature of course.
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OpenStudy (anonymous):
\[1 \over 2\] oh boy thanks lo
OpenStudy (anonymous):
You are welcome :)