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2sqrt{x+2}-sqrt{x-3}=sqrt{x+9}
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\[2\sqrt{x+2}-\sqrt{x-3}=\sqrt{x+9}\]
Square all terms. It would help
I'm still confused..
I'm solving it... gimme a second
ok
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\[2(x+2)^.5 - (x-3)^.5 = (x+9)^.5\] \[2(x+2)^.5 = (x+9)^.5 + (x-3)^.5\] \[4(x+2) = (x+9) + (x-3) + 2(x+9)^.5(x-3)^.5\] \[4x+8=2x+6 + 2(x+9)^.5 + (x-3)^.5\] x+1= (x+9)^.5(x-3)^.5
square both sides to get x=7 sry g2g
well i have to go but thanks anyways
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