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what is the first partial dervative of f(x,y)=x^y to the respect of y
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treat x like a contstant what is the derivative of f(y)=3^y lnf(y)=ln3^y lnf(y)=yln3 f'(y)/f(y)=ln3 f'(y)=ln3*f(y) f'(y)=ln3*3^y so if we have f(x,y)=x^y, then f_y=lnx*x^y
brb i have to brush my teeth
lnf(y)=yln3,f'(y)/f(y)=ln3 how this step is pertformed?
i took derivative of both sides
what is the derivative of f(x)=ln(x^2-1)
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f'(x)=(x^2-1)'/(x^2-1)=2x/(x^2-1)
that sounds about right. i am going to try it out
yay fun
thank you
great! i'm glad it worked out for you
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who gave me that medal? thanks whoever lol
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