Question

4+2/x / x/3+1/6

can someone help me solve this please

Answer 1

\[\frac{\frac{4+2}{x}}{\frac{x}{3}+\frac{1}{6}}\]this thing?

Answer 2

is there and "=" sign or is this a compound fraction?

Answer 3

solve might mean simplify ;) just my assumption tho

Answer 4

\[4 + 2/x \div x/3 + 1/6\]

Answer 5

in that case multiply top and bottom by 6x to clear fractions. or if you want you can do the subtraction in the denominator, and then divide by multiplying by the reciprocal of the denominator (after you subtract).

Answer 6

multiply everything by 6x could work

Answer 7

ooooh
\[4+\frac{2}{x} \div
\frac{x}{3} + \frac{1}{6}\]
?

Answer 8

yes that

Answer 9

12/x

Answer 10

can you tell me how you got the answer please

Answer 11

\[4+\frac{2}{x} \times \frac{3}{x} + \frac{1}{6}=4+
\frac{1}{6}+\frac{6}{x^2}=\frac{25}{6}+\frac{6}{x^2}\]

Answer 12

24x+12 12(2x+1)
------- = -------- = 4 if i did it right :)
6x +3 3(2x+1)

Answer 13

\[4+2/x=(4x+2)/x and x/3+1/6=(2x+1)/6. Then 4x+2/6 multiplied by 6/(2x+1) is equal \to 12/x\]

Answer 14

sorry i did not realize it was \[\frac{\frac{x+2}{x}}{\frac{x}{3}+\frac{1}{6}}\]

Answer 15

but i see an error in mine :)

6x(x/3) = 2x^2

Answer 16

24x +12
-------- perhaps?
2x^2 +x

Answer 17

it it perhaps
\[\frac{4+\frac{2}{x}}{\frac{x}{3}+\frac{1}{6}}\]?

Answer 18

\[\frac{4x+2}{x}*\frac{6}{2x+1}\]

Answer 19

12/x