Question

how do you solve a quadratic equation using the quadratic formula. Can someone explain this and show me an example so i get it...

Answer 1

\[ax^2 + bx +c = 0 \implies x=\frac{-(b) \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}\]

Answer 2

did you look at that scan i made for you?

Answer 3

Just plug them in

Answer 4

yes...I could not hardly read it..
sorry

Answer 5

ok nvm then

Answer 6

2x^2 + 10x + 3 = 0
a = 2
b = 10
c =3
D = sqrt(b^2-4ac) = sqrt (100-24) = sqrt(76)
x = -b +- sqrt (D)
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2a

Answer 7

So basically if you get something of the form you have on the right you plug it in to the formula on the left and you find the x values that make the right hand equation true.

Answer 8

Err.. I have a hard time with right/left. So reverse what I said ;)

Answer 9

Thank you..lol

Answer 10

i hate right and left
i use postive and negative when i talk

Answer 11

i say lets go in the positive direction hoping people think i mean is it right?

Answer 12

I appreciate all the help

Answer 13

or left?

Answer 14

ok

Answer 15

i think its right

Answer 16

polpak can i challenge you?

Answer 17

lol

Answer 18

with?