evaluate the integral of e^(3x)cos(4x)dx
integration by parts where u=cos(4x) and dv=e^3x
\[\int\limits_{}^{}e ^{3x}(e ^{i4x}+e ^{-i4x})dx/2\]\[e ^{(3+4i)x}/(3+4i)+e ^{(3-4i)}/(3-4i)\]
or Euler's Identity which ever one comes easier to you..LOL
the expression will be divided by 2.
now you can just solve to get a ans.e^3x(3cos4x+4sin3c)/25+c where c is the integration constant.
\[\frac{1}{25} e^{3 x} (3 \text{Cos}[4 x]+4 \text{Sin}[4 x]) \]from Mathematica 8
wow, u are so smart, you can copy answers out of a software package :/
thank u :) u forgot the plus C robtobey
see these videos if you want. http://www.youtube.com/watch?v=-ikhaXsiJU8&feature=related http://www.youtube.com/watch?v=XO6b4zhZgOs&feature=related
to do it algebraically involves two steps of integration by parts
I think they most likely wanted it done algebraically
first video does it algebraically ( which is most likely the way they want you to do it
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