Question

Help please, Divide
(x³-x+8) / (x-2)

Answer 1

x^3-x+8=x^3-2x^2+2x^2-4x+3x-6+14
=x^2(x-2)+2x(x-2)+3(x-2)+14=(x^2+2x+3)(x-2)+14
(x^3-x+6)/(x-2) =x^2+2x+3+[14/(x-2)]

Answer 2

...huh?

Answer 3

what?

Answer 4

im trying to writ this down on paper but... you lost me @ the second step

Answer 5

see i have rewrite the expression so that i can take (x-2) common.

Answer 6

see you have to divide with x-2

Answer 7

i have introduced -2x^2 to make with x^3 as x^2(x-2). and i have add 2x^2 to nullify it...

Answer 8

i have written -x as -4x+3x. and 8 as -6 +14.

Answer 9

ghhosst.............

Answer 10

have you now understood.

Answer 11

x^2 +2x +3
--------------
x-2 | x^3 -x +8
-x^3 +2x^2
-----------
2x^2 -x +8
-2x^2 +4x
------------
3x +8
-3x +6
--------
14 <- remainder

Answer 12

yea :) i c

Answer 13

the way it was written just threw me off, but i see how its done now thank you :)

Answer 14

how did yu get x^2 +2x +3 ?

Answer 15

simply we divided

Answer 16

nvm.. yu put the answer on the top. cool

Answer 17

see i had
x^3-x+8=x^2(x-2)+2x(x-2)+3(x-2)+14=(x^2+2x+3)(x-2)+14
so taking (x-2 common from the first three terms i have (x^2+2x +3)(x-2)