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If f(x) = sin(x) for all x, then the average value of f on the interval [0, π] is (A) ½ (B) 1/π (C) π/2 (D) 2/π
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D
\[1/\pi \int\limits_{0}^{\pi }\sin x dx =1/\pi (-c0sx)_{0}^{\pi }\]
how1/pi?
to get the average...
why we take average??????
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because your question says...to find average...
alright then why the average of pi????????
the interval is given [0, pi ]
hello??????????
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