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OpenStudy (anonymous):
Can I go any farther from here: Log(2x)? If yes, what property should I use?
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OpenStudy (anonymous):
Depends on what you are doing, if you are expanding the log you could write it as:
log(2) + log(x)
OpenStudy (anonymous):
I was trying to do exactly the same. I was not sure if I could do that
OpenStudy (anonymous):
I was asked to get the ln of y
OpenStudy (anonymous):
then you need to take the ln of both sides.
OpenStudy (anonymous):
applying the log properties I end up with:
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OpenStudy (anonymous):
Is there something else I can do now?
OpenStudy (anonymous):
specially with the term ln(2x-1)?
OpenStudy (anonymous):
The only part you need to fix is that -(ln(5x^2)) should be -(ln(5)+2ln(x))
OpenStudy (anonymous):
because in the problem only x is raised to the 2nd power and not the 5. the ln(2x-1) is in simplest form.
OpenStudy (anonymous):
So that must be the answer, right? Of course changing 2(ln5+lnx) by ln5+2lnx
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OpenStudy (anonymous):
exactly (also make sure that end is in parentheses and negated as it's in the denominator)
OpenStudy (anonymous):
I suppose this is the answer
OpenStudy (anonymous):
That's it
OpenStudy (anonymous):
Ok thank you very much for your help
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