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Mathematics 20 Online
OpenStudy (anonymous):

Can I go any farther from here: Log(2x)? If yes, what property should I use?

OpenStudy (anonymous):

Depends on what you are doing, if you are expanding the log you could write it as: log(2) + log(x)

OpenStudy (anonymous):

I was trying to do exactly the same. I was not sure if I could do that

OpenStudy (anonymous):

I was asked to get the ln of y

OpenStudy (anonymous):

then you need to take the ln of both sides.

OpenStudy (anonymous):

applying the log properties I end up with:

OpenStudy (anonymous):

Is there something else I can do now?

OpenStudy (anonymous):

specially with the term ln(2x-1)?

OpenStudy (anonymous):

The only part you need to fix is that -(ln(5x^2)) should be -(ln(5)+2ln(x))

OpenStudy (anonymous):

because in the problem only x is raised to the 2nd power and not the 5. the ln(2x-1) is in simplest form.

OpenStudy (anonymous):

So that must be the answer, right? Of course changing 2(ln5+lnx) by ln5+2lnx

OpenStudy (anonymous):

exactly (also make sure that end is in parentheses and negated as it's in the denominator)

OpenStudy (anonymous):

I suppose this is the answer

OpenStudy (anonymous):

That's it

OpenStudy (anonymous):

Ok thank you very much for your help

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