Question

Karin is playing a game at an after school carnival. There are a number of table tennis balls in a bag, and 1/3 of them are marked as prize-winners. A player randomly selects a ball from the bag, checks to see if they won a prize, and then replaces the ball. If karin plays the game 12 times, what is the probability that she will win a prize exactly 4 times?

A.) 0.0004
B.) 0.012
C.) 0.238
D.)0.25

Answer 1

anything?

Answer 2

the probability of winning a prize in one try is 1/3. Since the sample space remains the same for all tries, as the ball is replaced, we caN use binomial distribution in this.
The prob. of winning 4 out of 12 is:
12C4 (1/3)^4 (2/3)^8

Answer 3

is 12C4 suppose to be 12/4?

Answer 4

its 12!/(4!)(8!)

Answer 5

so i got 11880/ 24

Answer 6

which is 495

Answer 7

so multiply it by the others...

Answer 8

(1/3)^4 (2/3)^8?
so i got 1/81 and 256/6561 now wat...

Answer 9

multiply the three

Answer 10

what 3?