Question

Find the vertices and asymptotes of the hyperbola.

25y^2 - 16x^2 = 400

Answer 1

\[y^2/(400/25) - x^2/(400/16) =1\]

Answer 2

\[y^2/(4)^2- x^2/(5)^2= 1\]

Answer 3

shouldnt it be 25/400 and not the other way around

Answer 4

no 25 is multiplied with y^2

Answer 5

y=(+/-)b/a x are the asymptotes

Answer 6

ok so the asymptote..
y=+-4/5x

Answer 7

then does that mean the vertices are (0,+-4)

Answer 8

Yes uxma but as you are taking 400 from the left hand side it should be the denominator in this case

Answer 9

oh..i made a mistake, the axis of hyperbola is y axis

Answer 10

right ishan, n then 25 comes in the denominator of 400 :)

Answer 11

So am i still right then?
y=+-4/5x
and (0,+-4)

Answer 12

So am i still right then? y=+-4/5x and (0,+-4)

Answer 13

right :)

Answer 14

sweet thanks

Answer 15

54 to99 simplest form