A student club has 20 members. How many ways can the club choose a President, Secretary, and Treasurer? A. 6,840 B. 8,000 C. 2,280
Would you have to make a table? (:
no just mulitply \[20\times 19\times 18\]
Ahhhh ok :)
P(8, 5) = A. 40,320 B. 1,680 C. 6,720 so then wouldnt the answer to this one be A?
This is a combination/permutation problem. Since "order" does matter, ie, if Sally, Bob and Mike are the three officers, there can be multiple ways to fill the positions: Sally could be Pres, Bob Sec, and Mike Treas, or Sally could be Sec, Bob Pres, Mike Treas, and so on. Thus, this is a permutation. If order did not matter, ie, all three held the same title, then it would be a combination. A permutation can be written as nPr where n=total group, P means permutation, and r=number chosen. Thus, this would be 20P3.
Ohhh >.< so satellite was wrong?
satellite is correct, but I am giving you the long answer. :P
Ahhh yea ok :) So for the second one wouldnt it be A? (:
Permutation is calculated as n!/(n-r)! For #1, this is 20!/(20-3)! = 20*19*18. For #2, it is 8!/(8-5)!. This equals 8*7*6*5*4*3*2*1/(3*2*1) which equals 8*7*6*5*4. See why? So A is not correct...
Do you know what is?
Yes it would be C correct?
Yep :)
Woo!! 100%! :) Thanks r u a teacher? :D
yw. No, not a teacher.
Well you definitely should be one! (: Both of you!
Thanks. ;)
Yea getting ready to take a assessment on my online school so i might be posting a few more questions ^_^
cheater! lol
Haha not cheating if ur old computer hard drive crashed and now u cant access ur notes!! >.< and finals are almost here too! im soooo stressed all my notes. just, gon.
gone*
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