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Find the vector v with the given magnitude and the same direction as you. Magnitude of v = 4, direction u = <1,1>
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<4,4>
that aint it lol
It must be a 1:1 ratio?
<4cos(45), 4sin(45)>
Is there a formula or is it a guess?
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that is the answer; to get normal looking numbersl just plug it into a calculator
\[<2\sqrt{2},2\sqrt(2)>\]
i know the direction is 45 degress (1,1) and the length of the thing is 4; so i used trig :)
But what if magnitude is 2 and direction <sqrt(3),3>?
compute the unit vector along u
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then multiply it by 2
thats what...30 or 60 degress?
<2cos(60), 2sin(60>)
yeah ur right
Excuse me, I need to go to class. Thank you.
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suppose C is a 3x3 matrix such that det(C )=2. then det(C+C) is equal to????? PLEASE, help!!
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