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Mathematics 15 Online
OpenStudy (anonymous):

Find the vector v with the given magnitude and the same direction as you. Magnitude of v = 4, direction u = <1,1>

OpenStudy (amistre64):

<4,4>

OpenStudy (amistre64):

that aint it lol

OpenStudy (anonymous):

It must be a 1:1 ratio?

OpenStudy (amistre64):

<4cos(45), 4sin(45)>

OpenStudy (anonymous):

Is there a formula or is it a guess?

OpenStudy (amistre64):

that is the answer; to get normal looking numbersl just plug it into a calculator

OpenStudy (amistre64):

\[<2\sqrt{2},2\sqrt(2)>\]

OpenStudy (amistre64):

i know the direction is 45 degress (1,1) and the length of the thing is 4; so i used trig :)

OpenStudy (anonymous):

But what if magnitude is 2 and direction <sqrt(3),3>?

OpenStudy (anonymous):

compute the unit vector along u

OpenStudy (anonymous):

then multiply it by 2

OpenStudy (amistre64):

thats what...30 or 60 degress?

OpenStudy (amistre64):

<2cos(60), 2sin(60>)

OpenStudy (anonymous):

yeah ur right

OpenStudy (anonymous):

Excuse me, I need to go to class. Thank you.

OpenStudy (anonymous):

suppose C is a 3x3 matrix such that det(C )=2. then det(C+C) is equal to????? PLEASE, help!!

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