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Mathematics 15 Online
OpenStudy (anonymous):

These right cones are similar. H = , h = Volume of large cone = Volume of small cone = Volume of large cone = ------------------ Volume of small cone

OpenStudy (anonymous):

OpenStudy (anonymous):

what 64?

OpenStudy (anonymous):

the volume of large cone

OpenStudy (anonymous):

Big cone:\[h= \sqrt{20^{2}-12^{2}}=16\]\[v=1/3\pi12^{2}(16)=2,412,74cm ^{3}\] Small cone: let h for the heigh small coin ratio :3/12=h/16 \[ V= 1/3\pi3^{2}(4)=37.7cm ^{3}\] vol larg 2.412.74 ------- = --------- = 64cm^3 Vo sma 37.7

OpenStudy (anonymous):

u ri

OpenStudy (anonymous):

more?

OpenStudy (anonymous):

please..

OpenStudy (anonymous):

Ok each help give me one medal

OpenStudy (anonymous):

ok it a deal ^_^

OpenStudy (anonymous):

ok I try , but I'm slow

OpenStudy (anonymous):

if you not sure than I have to use 9/25 ratio and I think no choice

OpenStudy (anonymous):

small: V= A base*h 324=9*h h =324/9 h =36 big: 9/25=36/h cross and mutip 9h=36*25 h=900/9 h = 100 V larg : 9/25=324/V cross * 9V=25*324 V = 8.100/9 V = 900

OpenStudy (anonymous):

volum S 324 9 ------ = ----- = ----- volum B 900 25

OpenStudy (anonymous):

h 36 9 --- = --- = ---- H 100 25

OpenStudy (anonymous):

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