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find the coefficient of x^6 in the expansion of (2x+3)^10
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start by multiplying (2x+3) by itself 10 times. add up all the coefficients of like terms. see what the coefficient of x^6 is
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what is (2x+3) by itself ten times
(2x+3)(2x+3)(2x+3)(2x+3)(2x+3)(2x+3)(2x+3)(2x+3)(2x+3)(2x+3)
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I think you can be a little less crude about it, and simply write down: \[ \binom{10}{6} \times 2^6 \times 3^4 \]
Where \[\binom{n}{r} = ^nC_r = \frac{n!}{r!(n-r)!}\]
Newton is right. its much easier to do it his way.
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